Simplify Radicals & Calculate Expressions: A Step-by-Step Guide
Hey guys! Today, we're diving into the fascinating world of radicals and radical expressions. We'll be simplifying some complex radical expressions and tackling calculations involving various roots. So, grab your notebooks, and let's get started!
1) Simplifying Radicals
Simplifying radicals involves breaking down the radicand (the number inside the root) into its prime factors and then extracting any perfect powers. This makes the radical expression cleaner and easier to work with. Let's tackle the expressions you provided:
c) Simplifying Β³β378 - Β³β896 + Β³β1750
This expression involves cube roots, so we need to find perfect cubes within the radicands. Let's break down each term:
First, let's consider Β³β378. We need to find the prime factorization of 378.
378 = 2 Γ 189 = 2 Γ 3 Γ 63 = 2 Γ 3 Γ 3 Γ 21 = 2 Γ 3 Γ 3 Γ 3 Γ 7 = 2 Γ 3Β³ Γ 7
So, Β³β378 = Β³β(3Β³ Γ 2 Γ 7) = 3Β³β(2 Γ 7) = 3Β³β14.
Next, let's simplify Β³β896. Factoring 896, we have:
896 = 2 Γ 448 = 2 Γ 2 Γ 224 = 2 Γ 2 Γ 2 Γ 112 = 2 Γ 2 Γ 2 Γ 2 Γ 56 = 2 Γ 2 Γ 2 Γ 2 Γ 2 Γ 28 = 2 Γ 2 Γ 2 Γ 2 Γ 2 Γ 2 Γ 14 = 2β· Γ 7 = 2βΆ Γ 2 Γ 7 = (2Β²)Β³ Γ 2 Γ 7
Thus, Β³β896 = Β³β(2βΆ Γ 2 Γ 7) = Β³β((2Β²)Β³ Γ 2 Γ 7) = 2Β² Β³β(2 Γ 7) = 4Β³β14.
Now, let's break down Β³β1750. Factoring 1750 gives us:
1750 = 2 Γ 875 = 2 Γ 5 Γ 175 = 2 Γ 5 Γ 5 Γ 35 = 2 Γ 5 Γ 5 Γ 5 Γ 7 = 2 Γ 5Β³ Γ 7
Therefore, Β³β1750 = Β³β(5Β³ Γ 2 Γ 7) = 5Β³β(2 Γ 7) = 5Β³β14.
Now we can substitute these simplified radicals back into the original expression:
Β³β378 - Β³β896 + Β³β1750 = 3Β³β14 - 4Β³β14 + 5Β³β14
Combine the terms:
(3 - 4 + 5)Β³β14 = 4Β³β14
So, the simplified expression is 4Β³β14.
d) Simplifying β1188 - Β³β891 + 2β΄β2673
This expression involves square roots, cube roots, and fourth roots, making it a bit more challenging. We'll simplify each term individually.
First, consider β1188. Let's find the prime factorization of 1188:
1188 = 2 Γ 594 = 2 Γ 2 Γ 297 = 2Β² Γ 3 Γ 99 = 2Β² Γ 3 Γ 3 Γ 33 = 2Β² Γ 3 Γ 3 Γ 3 Γ 11 = 2Β² Γ 3Β³ Γ 11
So, β1188 = β(2Β² Γ 3Β³ Γ 11) = β(2Β² Γ 3Β² Γ 3 Γ 11) = 2 Γ 3β(3 Γ 11) = 6β33.
Next, let's simplify Β³β891. Factoring 891, we get:
891 = 3 Γ 297 = 3 Γ 3 Γ 99 = 3 Γ 3 Γ 3 Γ 33 = 3 Γ 3 Γ 3 Γ 3 Γ 11 = 3β΄ Γ 11
Thus, Β³β891 = Β³β(3β΄ Γ 11) = Β³β(3Β³ Γ 3 Γ 11) = 3Β³β(3 Γ 11) = 3Β³β33.
Now, let's break down β΄β2673. Factoring 2673 gives us:
2673 = 3 Γ 891 = 3 Γ 3 Γ 297 = 3 Γ 3 Γ 3 Γ 99 = 3 Γ 3 Γ 3 Γ 3 Γ 33 = 3 Γ 3 Γ 3 Γ 3 Γ 3 Γ 11 = 3β΅ Γ 11
Therefore, β΄β2673 = β΄β(3β΅ Γ 11) = β΄β(3β΄ Γ 3 Γ 11) = 3β΄β(3 Γ 11) = 3β΄β33.
Now we substitute these simplified radicals back into the original expression:
β1188 - Β³β891 + 2β΄β2673 = 6β33 - 3Β³β33 + 2(3β΄β33) = 6β33 - 3Β³β33 + 6β΄β33
Since the radicals are different (β33, Β³β33, and β΄β33), we cannot combine them further. So, the simplified expression is 6β33 - 3Β³β33 + 6β΄β33.
2) Calculating Radical Expressions
Now, let's move on to calculating expressions involving radicals. We'll use the properties of radicals to simplify and then compute the results.
a) Calculating β18 β’ β15
To calculate this, we use the property βa β’ βb = β(a β’ b). So:
β18 β’ β15 = β(18 β’ 15) = β270
Now, simplify β270 by finding its prime factorization:
270 = 2 Γ 135 = 2 Γ 3 Γ 45 = 2 Γ 3 Γ 3 Γ 15 = 2 Γ 3 Γ 3 Γ 3 Γ 5 = 2 Γ 3Β³ Γ 5
So, β270 = β(3Β³ Γ 2 Γ 5) = β(3Β² Γ 3 Γ 2 Γ 5) = 3β(3 Γ 2 Γ 5) = 3β30.
Therefore, β18 β’ β15 = 3β30.
b) Calculating β192 : β8
Using the property βa / βb = β(a / b), we have:
β192 : β8 = β(192 / 8) = β24
Now, simplify β24:
24 = 2 Γ 12 = 2 Γ 2 Γ 6 = 2 Γ 2 Γ 2 Γ 3 = 2Β³ Γ 3
Thus, β24 = β(2Β³ Γ 3) = β(2Β² Γ 2 Γ 3) = 2β(2 Γ 3) = 2β6.
So, β192 : β8 = 2β6.
c) Calculating 3β12 β’ β21
First, let's multiply the radicals using the property βa β’ βb = β(a β’ b):
3β12 β’ β21 = 3β(12 β’ 21) = 3β252
Now, simplify β252:
252 = 2 Γ 126 = 2 Γ 2 Γ 63 = 2Β² Γ 3 Γ 21 = 2Β² Γ 3 Γ 3 Γ 7 = 2Β² Γ 3Β² Γ 7
So, β252 = β(2Β² Γ 3Β² Γ 7) = 2 Γ 3β7 = 6β7
Substitute this back into the expression:
3β252 = 3(6β7) = 18β7.
Therefore, 3β12 β’ β21 = 18β7.
d) Calculating β΄β16 β’ β΄β9 : β΄β3
Using the properties β΄βa β’ β΄βb = β΄β(a β’ b) and β΄βa / β΄βb = β΄β(a / b), we get:
β΄β16 β’ β΄β9 : β΄β3 = β΄β(16 β’ 9) / β΄β3 = β΄β(16 β’ 9 / 3) = β΄β(16 β’ 3) = β΄β48
Now, simplify β΄β48:
48 = 2 Γ 24 = 2 Γ 2 Γ 12 = 2 Γ 2 Γ 2 Γ 6 = 2 Γ 2 Γ 2 Γ 2 Γ 3 = 2β΄ Γ 3
So, β΄β48 = β΄β(2β΄ Γ 3) = 2β΄β3.
Therefore, β΄β16 β’ β΄β9 : β΄β3 = 2β΄β3.
Conclusion
We've successfully simplified radicals and calculated radical expressions by breaking down radicands into prime factors and using the properties of radicals. Remember, the key is to identify perfect powers within the roots and simplify step by step. Keep practicing, and you'll become a radical master in no time! Keep up the great work, guys!